直接看代码:
--现有一端递归序列串:['房建', 'aaa', ''bbb, '建设用地批准书'],需要查询匹配树形结构内部某一段的所有值
--用到了递归查询
--双向递归,确定递归头和递归尾
WITH RECURSIVE resEnd AS (SELECT id, parent_id, level, name, project_id, business_hnical_folderWHERE project_id='1163' AND business_id='1163' AND type=3 AND name = '规划红线内的道路、园林绿化、喷灌设施等竣工图'UNIONSELECT b.id, b.parent_id, b.level, b.name, b.project_id, b.business_idFROM resEnd a INNER hnical_folder b ON a.parent_id = b.id
),resBegin AS (SELECT id, parent_id, level, name, project_id, business_hnical_folderWHERE project_id='1163' AND business_id='1163' AND type=3 AND name = '房建'UNIONSELECT b.id, b.parent_id, b.level, b.name, b.project_id, b.business_id-- 从尾部结果集中递归查找,提升查找效率FROM resBegin a INNER JOIN resEnd b ON a.id = b.parent_id
)
SELECT a.* from resEnd a INNER JOIN resBegin b ON a.id = b.id ORDER BY a.level;
结果如下:
本文发布于:2024-01-30 18:37:12,感谢您对本站的认可!
本文链接:https://www.4u4v.net/it/170661103622020.html
版权声明:本站内容均来自互联网,仅供演示用,请勿用于商业和其他非法用途。如果侵犯了您的权益请与我们联系,我们将在24小时内删除。
留言与评论(共有 0 条评论) |