在leetcode上有这样的一道题:
查询中第二高的薪水值,不存在则返回null
SELECT
(SELECT DISTINCT salary FROM employee GROUP BY salary DESC LIMIT 1,1) AS SECOND
或者
SELECT (
SELECT DISTINCT Salary FROM Employee ORDER BY Salary DESC LIMIT 1 OFFSET 1
)AS SECOND
或者
SELECT
CASE COUNT(1)
WHEN 1 THEN NULL
ELSE MIN(salary) END AS SecondHighestSalary
FROM
(SELECT salary FROM employee GROUP BY salary ORDER BY salary DESC LIMIT 2) t
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