对ASCLL码表中95个可视化字符的支持

对ASCLL码表中95个可视化字符的支持

#对ASCLL码表中95个可视化字符的支持def enChar(x,key):# 加密xid = ord(x)-first_ascll # 明文编号yid = (xid+key) % n # 密文编号y = chr(first_ascll+yid) # 求出密文字符return yfirst_ascll = ord(' ') # 起始字符
n = 95 # 字符总数def Caesar(text,key):result = ''for x in text:# 字符范围if ' '<=x<='~':x = enChar(x, key)result = result + xreturn resulttext = 'Attack Tonight!'
key = 2
print(Caesar(text, -key))