HJ48 从单向链表中删除指定值的节点(java详解)

HJ48 从单向链表中删除指定值的节点(java详解)

LinkedList就解决了

public static void main(String[] args) {Scanner in = new Scanner(System.in);while (in.hasNextInt()) {int num = in.nextInt();LinkedList<Integer> list=new LinkedList<>();list.Int());for (int i = 1; i < num; i++) {int newNum = in.nextInt();int index = list.Int());list.add(index + 1, newNum);}ve((Integer) (in.nextInt())); // remove 是重载方法，将其转为 Integer，强制使用删除指定对象的方法for (int i : list) {System.out.print(i + " ");}}}