用列表解析式进行判断:
df["has_comment_or_not"] = ["1" if status != "null" else "0"
for status in df["comment_status"].apply(str)]
具体例子如下:
In [1]: import pandas as pd
In [2]: import numpy as np
In [3]: df = pd.DataFrame(
{"has_comment_or_not":['0','0','0','1','0','0'],
"comment_status":["null","null","120047007","null","null","122121"]}
)
In [4]: df
Out[4]:
has_comment_or_not comment_status
0 0 null
1 0 null
2 0 120047007
3 1 null
4 0 null
5 0 122121
In [5]: df["has_comment_or_not"] = ["1" if status != "null" else "0"
for status in df["comment_status"].apply(str)]
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