WordPress根据文章浏览量进行排序教程

WordPress根据文章浏览量进行排序教程

我们想要实现最多人看的功能就必须对WordPress的代码风格及编写规范有一定了解，因此仅适合具备一定编程基础的人进行二次开发或者直接使用现成的代码，接下来为大家分享一个WordPress根据文章浏览量进行排序教程。

将下方代码添加进functions.php外加一个php文件即可实现：

//根据浏览量从多到少进行排序function get_most_viewed_format($mode = '', $limit = 10, $show_date = 0, $term_id = 0, $beforetitle= '(', $aftertitle = ')', $beforedate= '(', $afterdate = ')', $beforecount= '(', $aftercount = ')') {global $wpdb, $post;$output = '';$mode = ($mode == '') ? 'post' : $mode;$type_sql = ($mode != 'both') ? "AND post_type='$mode'" : '';$term_sql = (is_array($term_id)) ? "AND $wpdb->_id IN (" . join(',', $term_id) . ')' : ($term_id != 0 ? "AND $wpdb->_id = $term_id" : '');$term_sql.= $term_id ? " AND $wpdb->term_taxonomy.taxonomy != 'link_category'" : '';$inr_join = $term_id ? "INNER JOIN $wpdb->term_relationships ON ($wpdb->posts.ID = $wpdb->term_relationships.object_id) INNER JOIN $wpdb->term_taxonomy ON ($wpdb->_taxonomy_id = $wpdb->_taxonomy_id)" : '';// database query$most_viewed = $wpdb->get_results("SELECT ID, post_date, post_title, (meta_value+0) AS views FROM $wpdb->posts LEFT JOIN $wpdb->postmeta ON ($wpdb->posts.ID = $wpdb->postmeta.post_id) $inr_join WHERE post_status = 'publish' AND post_password = '' $term_sql $type_sql AND meta_key = 'views' GROUP BY ID ORDER BY views DESC LIMIT $limit");if ($most_viewed) {foreach ($most_viewed as $viewed) {$post_ID = $viewed->ID;$post_views = number_format($viewed->views);$post_title = esc_attr($viewed->post_title);$get_permalink = esc_attr(get_permalink($post_ID));$output .= '<li><a href="'.get_permalink($post_ID).'">'.$post_title.'';if ($show_date) {$posted = date(get_option('date_format'), strtotime($viewed->post_date));$output .= "$beforedate $posted $afterdate";}$output .= "$beforecount $post_views $aftercount</a></li>";}} else {$output = "<li>N/A</li>n";}echo $output;}//在需要调用的地方插入下方代码<?php get_most_viewed_format(); ?>

本文转自六艺开源：阅读原文