问题 C: Linear Approximation
时间限制: 1 Sec 内存限制: 128 MB
[提交] [状态]
题目描述
Snuke has an integer sequence A of length N.
He will freely choose an integer b. Here, he will get sad if Ai and b+i are far from each other. More specifically, the sadness of Snuke is calculated as follows:
abs(A1−(b+1))+abs(A2−(b+2))+…+abs(AN−(b+N))
Here, abs(x) is a function that returns the absolute value of x.
Find the minimum possible sadness of Snuke.
Constraints
1≤N≤2×105
1≤Ai≤109
All values in input are integers.
输入
Input is given from Standard Input in the following format:
N
A1 A2 … AN
输出
Print the minimum possible sadness of Snuke.
样例输入 Copy
5
2 2 3 5 5
样例输出 Copy
2
提示
If we choose b=0, the sadness of Snuke would be abs(2−(0+1))+abs(2−(0+2))+abs(3−(0+3))+abs(5−(0+4))+abs(5−(0+5))=2. Any choice of b does not make the sadness of Snuke less than 2, so the answer is 2.
#include <iostream>
#include <cstdio>
#include <queue>
#include <string>
#include <cstring>
#include <algorithm>
#include <stack>
#include <map>
using namespace std;
#define INF 0x3f3f3f3fint main()
{int n,a[200010];long long avg=0;cin >> n;for(int i=1; i<=n; i++){cin >> a[i];a[i] -= i;}sort(a+1,a+1+n);avg = a[n/2+1];long long ans = 0;for(int i=1; i<=n; i++)ans += abs(a[i]-avg);cout << ans << endl;return 0;
}
注意:avg = a[n/2+1];
不是n/2 因为下标从1开始
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