从订单明细表(order_detail)中查询累积销售件数高于其所属品类平均数的商品,期望结果如下:
sku_id | name | sum_num | cate_avg_num |
---|---|---|---|
2 | 手机壳 | 302 | 110.5 |
5 | 破壁机 | 242 | 194.75 |
7 | 热水壶 | 252 | 194.75 |
8 | 微波炉 | 253 | 194.75 |
10 | 帐篷 | 299 | 290.5 |
11 | 烧烤架 | 320 | 290.5 |
12 | 遮阳伞 | 349 | 290.5 |
select sku_id,name,sum_num,cate_avg_num
from
(select t1.sku_id,si.name,t1.sum_num,avg(t1.sum_num) over (partition by si.category_id) cate_avg_num,(t1.sum_num - avg(t1.sum_num) over (partition by si.category_id)) flagfrom (select sku_id,sum(sku_num) sum_numfrom order_detailgroup by sku_id )t1left join sku_info si on t1.sku_id=si.sku_id
)t2
where flag > 0;set hive.pe.safety=false;
set de=nostrict;
select sku_id,name,sum_num,cate_avg_num
from (select od.sku_id,category_id,name,sum_num,avg(sum_num) over (partition by category_id) cate_avg_numfrom (select sku_id,sum(sku_num) sum_numfrom order_detailgroup by sku_id) odleft join(select sku_id,name,category_idfrom sku_info) skuon od.sku_id = sku.sku_id) t1
where sum_num > cate_avg_num;
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