Reorganize String
Given a string S, check if the letters can be rearranged so that two characters that are adjacent to each other are not the same.
If possible, output any possible result. If not possible, return the empty string.
Example
Input: S = “aab”
Output: “aba”
Solution
@collections处理字符串中各个字符出现的频率
class Solution:def reorganizeString(self, S: str) -> str:counter = collections.Counter(S)ret = '#'while counter:flag = Truefor item, times st_common():if ret[-1]!= item:ret+= itemcounter[item]-= 1if not counter[item]:del counter[item]flag = Falsebreakif flag:breakreturn ret[1::] if len(ret)==len(S)+1 else ''
本文发布于:2024-02-05 09:09:54,感谢您对本站的认可!
本文链接:https://www.4u4v.net/it/170728517865194.html
版权声明:本站内容均来自互联网,仅供演示用,请勿用于商业和其他非法用途。如果侵犯了您的权益请与我们联系,我们将在24小时内删除。
留言与评论(共有 0 条评论) |