访问修饰符 返回类型 方法名(参数列表){方法体;
}
方法分类:
/*** 使用方法进行星号打印*/
public class MethodDemo {//打印输出星号public void printStar() {System.out.println("**********************");}public static void main(String[] args) {//创建MethodDemo类的对象methodDemoMethodDemo methodDemo = new MethodDemo();//使用对象名.方法名()调用方法methodDemo.printStar();System.out.println("欢迎来到Java的世界");methodDemo.printStar();}
}
/*** 使用方法计算矩形面积*/
public class RectangleArea {//求矩形面积的方法public int area() {int length = 10;int width = 5;int calArea = length * width;return calArea;//返回语句返回面积}public static void main(String[] args) {RectangleArea rectangleArea = new RectangleArea();System.out.println("矩形的面积为:" + rectangleArea.area());}
}
/*** 使用方法求两个float类型数据的最大值,并在方法中将最大值输出*/
public class MaxDemo {//求最大值的方法public void max(float a, float b) {float max;if (a > b) {max = a;} else {max = b;}System.out.println("最大值是:" + max);}public static void main(String[] args) {MaxDemo maxDemo = new MaxDemo();float m = 2.1f, n = 3.7f;maxDemo.max(m, n);}
}
/*** 定义一个求n!的方法* 然后计算1!+2!+3!+4!+5!*/
public class FacDemo {//求n!的阶乘public int fac(int n){int s = 1;for(int i = 1; i <= n; i++){s *= i;}return s;}public static void main(String[] args) {FacDemo facDemo = new FacDemo();//求1!+2!+3!+4!+5!int sum = 0;for(int i = 1; i <= 5; i++){sum += facDemo.fac(i);}System.out.println("阶乘结果为:"+sum);}
}
/*** 使用方法打印输出数组的元素*/
public class ArrayMethod {//输出数组元素的方法public void printArray(int[] arr) {for (int n : arr) {System.out.print(n + " ");}System.out.println();//格式调整}public static void main(String[] args) {ArrayMethod arrayMethod = new ArrayMethod();int[] array = {10, 20, 30, 40, 50};arrayMethod.printArray(array);}
}
import java.util.Scanner;/*** 使用方法查找数组元素的值*/
public class ArraySearch {//查找数组元素值的方法public boolean search(int n, int[] arr) {boolean flag = false;//默认没找到for (int m : arr) {if (m == n) {flag = true;break;//使用break语句提高程序的效率}}return flag;}public static void main(String[] args) {Scanner sc = new Scanner(System.in);ArraySearch arraySearch = new ArraySearch();int[] array = {1, 2, 3, 4, 5};System.out.println("请输入要查询的值:");int n = sc.nextInt();boolean flag = arraySearch.search(n, array);if (flag) {System.out.println("找到了");} else {System.out.println("没找到");}}
}
/*** 定义三个方法,实现int、double和数组类型和的问题*/
public class MathDemo {//求两个int类型数的和public int plus(int a, int b) {return a + b;}//求两个double类型的数的和public double plus(double a, double b) {return a + b;}//求数组元素的累加和public int plus(int[] arr) {int sum = 0;for (int n : arr) {sum += n;}return sum;}public static void main(String[] args) {int m = 5, n = 10;int[] array = {1, 2, 3, 4, 5, 6};MathDemo mathDemo = new MathDemo();System.out.println("int类型的和:" + mathDemo.plus(m, n));System.out.println("double类型的和:" + mathDemo.plus(m, n));System.out.println("数组元素的累加和:" + mathDemo.plus(array));}
}
案例一:
public class ExchangeDemo1 {//定义交换方法public void swap(int a, int b) {int temp;System.out.println("交换前: a = " + a + ", b = " + b);temp = a;a = b;b = temp;System.out.println("交换后: a = " + a + ", b = " + b);}public static void main(String[] args) {int m = 4, n = 5;ExchangeDemo1 swapDemo = new ExchangeDemo1();System.out.println("交换前: m = " + m + ", n = " + n);swapDemo.swap(m, n);System.out.println("交换后: m = " + m + ", n = " + n);}
案例二:
public class ExchangeDemo2 {public void add(int n) {n++;System.out.println("方法中n的值:" + n);}public static void main(String[] args) {int n = 10;System.out.println("方法调用前n的值:" + n);ExchangeDemo2 exchangeDemo2 = new ExchangeDemo2();exchangeDemo2.add(n);System.out.println("方法调用后n的值:" + n);}
}
public class ArrayDemo {//定义一个用于修改数组某个元素值的方法public void update(int[] arr) {arr[3] = 15;System.out.println("修改后数组arr的元素为:");for (int n : arr) {System.out.print(n + " ");}System.out.println();}public static void main(String[] args) {ArrayDemo arrayDemo = new ArrayDemo();int[] array = {1, 2, 3, 4, 5};System.out.println("方法调用前数组array的元素为;");for (int n : array) {System.out.print(n + " ");}System.out.println();arrayDemo.update(array);System.out.println("方法调用后数组array的元素为;");for (int n : array) {System.out.print(n + " ");}System.out.println();}
}
案例一:
public class ArgsDemo1 {//求和public void n) {int sum = 0;for (int i : n) {sum += i;}System.out.println("sum = " + sum);}public static void main(String[] args) {ArgsDemo1 argsDemo = new ArgsDemo1();argsDemo.sum(1);argsDemo.sum(1, 2);argsDemo.sum(1, 2, 3);}
}
案例二:参数列表中如果有两个以上的参数,可变参数一定是在最后;可以将数组传递给可变参数列表,但是数组作为参数时,是不能将多个值传递给数组的
public class ArgsDemo2 {//查找public void search(int n, a) {boolean flag = false;for (int i : a) {if (i == n) {flag = true;break;}}if (flag) {System.out.println("找到了");} else {System.out.println("没找到");}}public static void main(String[] args) {ArgsDemo2 argsDemo2 = new ArgsDemo2();argsDemo2.search(3, 1, 2, 3, 4, 5);int[] a = {4, 5, 6, 7, 8};argsDemo2.search(3, a);}
}
Tips:若此时定义另一个search方法 -- public void search(int n, int[] array)
,并不是方法重载而是重复定义
案例:
public class ArgsDemo3 {public int plus(int a, int b) {System.out.println("不带可变参数列表的方法被调用");return a + b;}public int a) {int sum = 0;for (int i : a) {sum += i;}System.out.println("带可变参数列表的方法被调用");return sum;}public int plus(int[] arr, a) {int sum1 = 0, sum2 = 0;for (int i : arr) {sum1 += i;}for (int i : a) {sum2 += i;}return sum1 + sum2;}public static void main(String[] args) {ArgsDemo3 argsDemo3 = new ArgsDemo3();System.out.println("和为:" + argsDemo3.plus(1, 2));int[] arr = {1, 2, 3};System.out.println("可变参数列表和数组同时作为方法参数" + argsDemo3.plus(arr, 1, 2, 3, 4));}
}
本文发布于:2024-02-02 01:38:19,感谢您对本站的认可!
本文链接:https://www.4u4v.net/it/170681331740582.html
版权声明:本站内容均来自互联网,仅供演示用,请勿用于商业和其他非法用途。如果侵犯了您的权益请与我们联系,我们将在24小时内删除。
留言与评论(共有 0 条评论) |